Coweight lattice $A^*_n$ and lattice simplices

23 Mar 2020 Zabolotskiy Andrey

There exist as many index-$k$ sublattices of the hexagonal lattice up to isometry as there exist lattice triangles with normalized volume $k$ up to unimodular equivalence, which can be explained using orbifolds. In dimension 3, it was noted that the number of sublattices of the fcc and the bcc lattices and the number of lattice tetrahedra all seem to be the same... (read more)

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  • COMBINATORICS
  • METRIC GEOMETRY